-12x^2+280x+3800=0

Solution for -12x^2+280x+3800=0 equation:

-12x^2+280x+3800=0

a = -12; b = 280; c = +3800;
Δ = b2-4ac
Δ = 2802-4·(-12)·3800
Δ = 260800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{260800}=\sqrt{1600*163}=\sqrt{1600}*\sqrt{163}=40\sqrt{163}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(280)-40\sqrt{163}}{2*-12}=\frac{-280-40\sqrt{163}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(280)+40\sqrt{163}}{2*-12}=\frac{-280+40\sqrt{163}}{-24}
$